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Forum Thread

Best Way To Win Higher or Lower?

Forum-Index Discussion Best Way To Win Higher or Lower?
Kittenface8
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Trainerlevel: 14

Forum Posts: 1
Posted: Mon, 14/05/2018 21:43 (7 Years ago)
I’m currently trying to do the Raylong quest involving winning higher or lower sixteen times. I’ve been using the strategy of if it’s over five, choose lower and if it’s under five, choose higher but have not had any luck. Is there a better strategy to winning or is it just luck? Thanks :p
Nezumi
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Posted: Tue, 15/05/2018 19:47 (7 Years ago)
It's really just luck. I managed to get on the Rank list with my chain once, but not since


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MangozBaka
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Forum Posts: 12
Posted: Tue, 15/05/2018 20:07 (7 Years ago)
I actually normally do higher if it is over 2 and then lower is really depending on what kinds of numbers that were under it.
Like once I had a 3 and it was one.
So its really depending!!
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YosukeHanamura77
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Posted: Wed, 16/05/2018 02:14 (7 Years ago)
Probability. if first is 9, try 'lower', etc
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Nightstooth
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Forum Posts: 134
Posted: Fri, 25/05/2018 00:50 (7 Years ago)
The game is based on probability as far as I can tell. If he chooses the number 9, you have a 9/10 probability (or 90% chance) of getting the answer right if you choose "lower" and 1/10 (or 10%) chance of getting it right when you choose "higher." At five, you have a 50% - 50% chance of getting it right no matter which one you chose so it is mainly luck when he picks numbers around the middle. (Of course, with it being probability, sometimes he picks the number 10 when his first number is 9 at about a 10% rate.)
TheBandedFlame
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Forum Posts: 238
Posted: Fri, 25/05/2018 00:58 (7 Years ago)
Ehhh... not true. He never picks a number twice. With this in mind, it's a chance out of nine. At 9 you have an 8/9 chance with lower, about 88.9% chance, while higher is 1/9, about 11.1%. At 5, you have a 4/9 percent chance at lower to 5/9 chance at higher.

Another way of thinking about it is it's always a 50% chance. This way of thinking is only if you believe that he already has two numbers. If he already has two numbers, it's the probability that he picks the smaller one first if you pick higher, or if he picks the larger one and you pick lower.
Nightstooth
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Posted: Fri, 25/05/2018 01:03 (7 Years ago)
Similiar enough to me. I'm not that good at math to do weird percentages in my head on the fly.
skycrax
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Posted: Mon, 28/05/2018 09:33 (7 Years ago)
So basically, it all depends on your luck.
WasabiBunny
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Posted: Wed, 01/12/2021 03:51 (3 Years ago)

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SuicidalNubby
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Forum Posts: 4
Posted: Mon, 02/06/2025 09:11 (17 Days ago)
Hear me out... I believe I managed to figure it out. It's the same in Coin Flip. Rather than 50.50 probability and luck, there's also technique. Like you need to figure out whether it's once or twice or thrice it's always three times. Like if you went with higher and then went with lower go again with higher and continue for 2 or 3 times including these. And if you next went with higher and won that round, repeat that for lower too the same amount as the higher. But don't keep continuing cause there may be change after 2 or 3 times of doing that. Either can be former if you went with latter or latter if you went with former.
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Gabssorry
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Posted: Mon, 02/06/2025 14:23 (16 Days ago)

Title: h or l

i would say its luck at the end